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1.75x^2-50x=125
We move all terms to the left:
1.75x^2-50x-(125)=0
a = 1.75; b = -50; c = -125;
Δ = b2-4ac
Δ = -502-4·1.75·(-125)
Δ = 3375
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3375}=\sqrt{225*15}=\sqrt{225}*\sqrt{15}=15\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-15\sqrt{15}}{2*1.75}=\frac{50-15\sqrt{15}}{3.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+15\sqrt{15}}{2*1.75}=\frac{50+15\sqrt{15}}{3.5} $
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